Here’s how you integrate a trig integral that contains tangents and secants where the tangent power is odd and positive. You’ll need the tangent-secant version of the Pythagorean identity:
Lop off a secant-tangent factor and move it to the right.
First, rewrite the problem:
Convert the remaining (even) tangents to secants with the tangent-secant version of the Pythagorean identity.
Now make the switch.
Solve with the substitution method with u = sec(x) and du = sec(x) tan(x)dx.