Quantum physics experiments take place in the lab frame, but you do scattering calculations in the center-of-mass frame, so you have to know how to relate the angle between the two frames.
Here's how this works: The following figure shows scattering in the lab frame.
![Scattering in the lab frame.](https://cdn.prod.website-files.com/6634a8f8dd9b2a63c9e6be83/669d46a95499852bf5000a88_398178.image0.jpeg)
One particle, traveling at
![image1.png](https://cdn.prod.website-files.com/6634a8f8dd9b2a63c9e6be83/669d46a95499852bf5000a79_398179.image1.png)
is incident on another particle that's at rest
![image2.png](https://cdn.prod.website-files.com/6634a8f8dd9b2a63c9e6be83/669d46a95499852bf5000a83_398180.image2.png)
and hits it. After the collision, the first particle is scattered at
![image3.png](https://cdn.prod.website-files.com/6634a8f8dd9b2a63c9e6be83/669d46a95499852bf5000a8f_398181.image3.png)
and the other particle is scattered at
![image4.png](https://cdn.prod.website-files.com/6634a8f8dd9b2a63c9e6be83/669d46a95499852bf5000ae3_398182.image4.png)
Now in the center-of-mass frame, the center of mass is stationary and the particles head toward each other. After they collide, they head away from each other at angles
![image5.png](https://cdn.prod.website-files.com/6634a8f8dd9b2a63c9e6be83/669d46a95499852bf5000a7f_398183.image5.png)
You have to move back and forth between these two frames — the lab frame and the center-of-mass frame — so you need to relate the velocities and angles (in a nonrelativistic way).
To relate the angles
![image6.png](https://cdn.prod.website-files.com/6634a8f8dd9b2a63c9e6be83/669d46a95499852bf5000a93_398184.image6.png)
you start by noting that you can connect
![image7.png](https://cdn.prod.website-files.com/6634a8f8dd9b2a63c9e6be83/669d46a95499852bf5000ac6_398185.image7.png)
using the velocity of the center of mass,
![image8.png](https://cdn.prod.website-files.com/6634a8f8dd9b2a63c9e6be83/669d46a95499852bf5000a9d_398186.image8.png)
In addition, here's what you can say about the velocity of particle 1 after it collides with particle 2:
![image9.png](https://cdn.prod.website-files.com/6634a8f8dd9b2a63c9e6be83/669d46a95499852bf5000aa5_398187.image9.png)
Now you can find the components of these velocities:
![image10.png](https://cdn.prod.website-files.com/6634a8f8dd9b2a63c9e6be83/669d46a95499852bf5000aa1_398188.image10.png)
Dividing the equation in the second bullet by the one in the first gives you
![image11.png](https://cdn.prod.website-files.com/6634a8f8dd9b2a63c9e6be83/669d46a95499852bf5000ad7_398189.image11.png)
But wouldn't it be easier if you could relate
![image12.png](https://cdn.prod.website-files.com/6634a8f8dd9b2a63c9e6be83/669d46a95499852bf5000ab5_398190.image12.png)
by something that didn't involve the velocities, only the masses, such as the following?
![image13.png](https://cdn.prod.website-files.com/6634a8f8dd9b2a63c9e6be83/669d46a95499852bf5000abb_398191.image13.png)
Well, you can. To see that, start with
![image14.png](https://cdn.prod.website-files.com/6634a8f8dd9b2a63c9e6be83/669d46a95499852bf5000adc_398202.image24.png)
And you can show that
![image15.png](https://cdn.prod.website-files.com/6634a8f8dd9b2a63c9e6be83/669d46a95499852bf5000aac_398193.image15.png)
You can also use the conservation of momentum to say what happens after the collision. In fact, because the center of mass is stationary in the center-of-mass frame, the total momentum before and after the collision is zero in that frame, like this:
![image16.png](https://cdn.prod.website-files.com/6634a8f8dd9b2a63c9e6be83/669d46a95499852bf5000aa8_398194.image16.png)
Therefore
![image17.png](https://cdn.prod.website-files.com/6634a8f8dd9b2a63c9e6be83/669d46a95499852bf5000ab8_398195.image17.png)
And after the collision,
![image18.png](https://cdn.prod.website-files.com/6634a8f8dd9b2a63c9e6be83/669d46a95499852bf5000b00_398196.image18.png)
which means that
![image19.png](https://cdn.prod.website-files.com/6634a8f8dd9b2a63c9e6be83/669d46a95499852bf5000ab1_398197.image19.png)
Also, if the collision is elastic, kinetic energy is conserved in addition to momentum, so that means the following is true:
![image20.png](https://cdn.prod.website-files.com/6634a8f8dd9b2a63c9e6be83/669d46a95499852bf5000ae6_398198.image20.png)
Substituting
![image21.png](https://cdn.prod.website-files.com/6634a8f8dd9b2a63c9e6be83/669d46a95499852bf5000afd_398199.image21.png)
into this equation gives you
![image22.png](https://cdn.prod.website-files.com/6634a8f8dd9b2a63c9e6be83/669d46a95499852bf5000ac9_398200.image22.png)
Given these two equations, you can redo
![image23.png](https://cdn.prod.website-files.com/6634a8f8dd9b2a63c9e6be83/669d46a95499852bf5000aef_398201.image23.png)
Dividing the magnitude of each side of
![image24.png](https://cdn.prod.website-files.com/6634a8f8dd9b2a63c9e6be83/669d46a95499852bf5000adc_398202.image24.png)
by the magnitude of the above equation gives you
![image25.png](https://cdn.prod.website-files.com/6634a8f8dd9b2a63c9e6be83/669d46a95499852bf5000a97_398203.image25.png)
And because you saw earlier that
![image26.png](https://cdn.prod.website-files.com/6634a8f8dd9b2a63c9e6be83/669d46a95499852bf5000ae9_398204.image26.png)
substituting
![image27.png](https://cdn.prod.website-files.com/6634a8f8dd9b2a63c9e6be83/669d46a95499852bf5000a97_398203.image25.png)
into this equation gives you at last
![image28.png](https://cdn.prod.website-files.com/6634a8f8dd9b2a63c9e6be83/669d46a95499852bf5000abb_398191.image13.png)
Okay, that relates
![image29.png](https://cdn.prod.website-files.com/6634a8f8dd9b2a63c9e6be83/669d46a95499852bf5000a93_398184.image6.png)
which is what you were trying to do. Using the relation
![image30.png](https://cdn.prod.website-files.com/6634a8f8dd9b2a63c9e6be83/669d46a95499852bf5000b0a_398208.image30.png)
you can rewrite
![image31.png](https://cdn.prod.website-files.com/6634a8f8dd9b2a63c9e6be83/669d46a95499852bf5000abb_398191.image13.png)
as the following:
![image32.png](https://cdn.prod.website-files.com/6634a8f8dd9b2a63c9e6be83/669d46a95499852bf5000b0d_398210.image32.png)
You can also relate
![image33.png](https://cdn.prod.website-files.com/6634a8f8dd9b2a63c9e6be83/669d46a95499852bf5000af7_398211.image33.png)
You can show that
![image34.png](https://cdn.prod.website-files.com/6634a8f8dd9b2a63c9e6be83/669d46a95499852bf5000af3_398212.image34.png)
which, using a little trig, means that
![image35.png](https://cdn.prod.website-files.com/6634a8f8dd9b2a63c9e6be83/669d46a95499852bf5000afa_398213.image35.png)
You've now related the angles between the lab and center-of-mass frames.