The trig function cosine, abbreviated cos, works by forming this ratio: adjacent/hypotenuse. In the figure, you see that the cosines of the two angles are as follows:
![image0.jpg](https://cdn.prod.website-files.com/6634a8f8dd9b2a63c9e6be83/669a1c437159a21bee8140da_439669.image0.jpeg)
![image1.jpg](https://cdn.prod.website-files.com/6634a8f8dd9b2a63c9e6be83/669a1c437159a21bee8140e8_439670.image1.jpeg)
The situation with the ratios is the same as with the sine function — the values are going to be less than or equal to 1 (the latter only when your triangle is a single segment or when dealing with circles), never greater than 1, because the hypotenuse is the denominator.
![image2.jpg](https://cdn.prod.website-files.com/6634a8f8dd9b2a63c9e6be83/669a1bfd6389266d150932b3_440253.image0.jpeg)
The two ratios for the cosine are the same as those for the sine — except the angles are reversed. This property is true of the sines and cosines of complementary angles in a right triangle (meaning those angles that add up to 90 degrees).
If theta and lambda are the two acute angles of a right triangle, then sin theta = cos lambda and cos theta = sin lambda.
Now for an example. To find the cosine of angle beta in a right triangle if the two legs are each
![image3.jpg](https://cdn.prod.website-files.com/6634a8f8dd9b2a63c9e6be83/669a1c437159a21bee8140cd_439672.image3.jpeg)
feet in length:
Find the length of the hypotenuse.
Using the Pythagorean theorem, a2 + b2 = c2, and replacing both a and b with the given measure, solve for c.
The hypotenuse is
feet long.
Use the ratio for cosine, adjacent over hypotenuse, to find the answer.